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cos
O
=

ABAC

ABAC
ąą
ąą
|
=
[1,4][3,2]
1713
|
=
(1)(3)42
+|
221
=
11
221
,
cos
B
=


BABC
BABC
ą
ą
|
ą
ą
=
[1,4][2,2]
|
178
=
3
34
,
cos
Y
=
CBCA

CBCA

ą
ą
|
ą
ą
=
[2,2][3,2]
813
|
=
1
26
.
MethodII
Sincethevectorsa,bandcformaclosedtriangle(Fig.1.9),we
obtain
abclthus
++=
,
bc
+=
a(wearelookingforcosα).
Wesquarebothsidesoftheequationandobtain:
b
2
+
2
bcc
|+
2
=
a
2
.
Weusethescalarproductpropertiesandcalculate:
bc
|=
bc
|
cos(
πO
)
=
bc
cos
O
,
b
2
=
b
2
=
13
,
c
2
=
c
2
=
17
and
a
2
=
a
2
=
8
,
thus
cos
O
=
b
2
+
2
c
bc
2
a
2
=
13178
21317
+
=
11
221
.
Similarly,formulaefortheotheranglescanbeobtained:
cos
B
=
a
2
+
2
c
ac
2
b
2
,
cos
Y
=
a
2
+
2
b
ab
2
c
2
.
TheformulaeobtainedabovepresenttheCarnot’stheorem(also
referredtoasthelawofcosines).
CHAPTER1
|
FUNDAMENTALSOFVECTORANDTENSORCALCULUS
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